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Because an inner join was defined, rows from the HumanResources.Employee table that do not have a matching row in the Person.Person table are not returned. The reverse is also true, in that rows from the Person.Person table that are not matched in the HumanResources .Employee table are not returned. The way to overcome this behavior is to use an OUTER JOIN operator.

System.Runtime.Remoting.Channels;

C. Integrated Security = True D. Trusted_Connection = Yes 2. If you must use a user name and password to connect to a database, where should you store the sensitive information A. Compiled in the application B. In an encrypted application configuration file C. In a resource file deployed with the application D. In the registry 3. What is the recommended method for securing sensitive connection string information A. Encrypting the data in the application configuration file B. Using a code obfuscator C. Using integrated security (Windows Authentication) D. Querying the user for his or her credentials at run time

System.Runtime.Remoting.Channels.Tcp;

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An outer join can be used to return all rows from one table and only information from rows that are in common from the other table, or it can return all rows from all tables in the JOIN clause. The word OUTER can be omitted from the syntax, but you must specify LEFT, RIGHT, or FULL. The LEFT and RIGHT operators can be used to specify from which table all the rows are returned. When you specify LEFT OUTER JOIN, all rows are returned from the table to the left of the keyword JOIN. This table is referred to as the outer table. You can accomplish the same thing with either a LEFT or RIGHT operator by changing the order in which the table names are referenced. For example, the following sample code returns all rows from the Person.Person table, along with the corresponding information from the matching rows in the HumanResources.Employee table. Figure 1-5 shows the result set from this query. Notice the NULL values in the JobTitle, VacationHours, and SickLeaveHours columns from the HumanResources.Employee table. These values are not available for rows in the Person.Person table that do not have corresponding information in the HumanResources.Employee table. Because the HumanResources.Employee table does not allow NULL values for these columns, it is obvious which rows were added to the result set by changing the INNER JOIN to a RIGHT OUTER JOIN. If NULL values were allowed, you would not be able to use the presence of NULL values alone to determine which rows were added by changing the join type:

MSLearning.5.PatientClasses;

To further practice and reinforce the skills you learned in this chapter, you can per form the following tasks:

4. In the Main method (Visual C#) or Sub Main (Visual Basic), type the following code. This code is used to instantiate an instance of the TCP channel.

SELECT FirstName, LastName, JobTitle, VacationHours, SickLeaveHours FROM HumanResources.Employee E RIGHT OUTER JOIN Person.Person P ON E.BusinessEntityID = P.BusinessEntityID;

'VB Dim channel As TcpClientChannel = New TcpClientChannel() //C# TcpClientChannel channel = new TcpClientChannel();

Review the chapter summary. Complete the case scenarios. These scenarios set up real-world situations involv ing the topics of this chapter and ask you to create a solution. Complete the additional practices. Take a practice test.

The same result set can be achieved by using a LEFT OUTER JOIN by reordering the table names, as in the following query:

5. Below the TcpClientChannel instance, type the following code to register the channel:

'VB ChannelServices.RegisterChannel(channel, False) //C# ChannelServices.RegisterChannel(channel, false);

SELECT FirstName, LastName, JobTitle, VacationHours, SickLeaveHours FROM Person.Person P LEFT OUTER JOIN HumanResources.Employee E

Summary

6. Below the channel registration, type the following code to register the remote Patient object:

'VB RemotingConfiguration.RegisterWellKnownClientType( _ GetType(Patient), "tcp://localhost:9000/Patient.rem") //C# RemotingConfiguration.RegisterWellKnownClientType( typeof(Patient), "tcp://localhost:9000/Patient.rem");

ON E.BusinessEntityID = P.BusinessEntityID;

7. Below the channel registration, type the following code to create an instance of the remote Patient type:

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